A) \[2\times {{10}^{-3}}M\] and \[5\times {{10}^{-12}}M\]
B) \[1\times {{10}^{3}}M\] and \[3\times {{10}^{-11}}M\]
C) \[0.02\times {{10}^{-3}}M\] and \[5\times {{10}^{-11}}M\]
D) \[3\times {{10}^{-2}}M\] and \[4\times {{10}^{-13}}M\]
Correct Answer: A
Solution :
Key Idea: Use the following formula to find concentration of \[O{{H}^{-}}\] ions. \[[{{H}^{+}}]=C\alpha \] \[[O{{H}^{-}}]=\frac{ionic\text{ }product\text{ }of\text{ }water}{[{{H}^{+}}]}\] Given, \[C=0.1\] \[\alpha =2%=\frac{2}{100}=0.02\] \[[{{H}^{+}}]=C\alpha \] \[=0.1\times 0.01\] \[=2\times {{10}^{-3}}\] \[[O{{H}^{-}}]=\frac{1\times {{10}^{-14}}}{2\times {{10}^{-3}}}\] \[=5\times {{10}^{-12}}\]
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