DUMET Medical DUMET Medical Solved Paper-2004

  • question_answer
    For a transistor, in a common emitter arrangement, the alternating current gain P is given by :

    A)  \[\beta ={{\left( \frac{\Delta {{l}_{C}}}{\Delta {{l}_{B}}} \right)}_{{{V}_{CE}}}}\]       

    B)  \[\beta ={{\left( \frac{\Delta {{l}_{B}}}{\Delta {{l}_{C}}} \right)}_{{{V}_{CE}}}}\]

    C)  \[\beta ={{\left( \frac{\Delta {{l}_{C}}}{\Delta {{l}_{E}}} \right)}_{{{V}_{CE}}}}\]

    D)  \[\beta ={{\left( \frac{\Delta {{l}_{E}}}{\Delta {{l}_{C}}} \right)}_{{{V}_{CE}}}}\]

    Correct Answer: A

    Solution :

     The AC current gain in an common-enitter transistor is denned as the ratio of the change in the collector current to the change in the base current at a constant collector to emitter voltage \[\beta ={{\left( \frac{\Delta \,{{i}_{C}}}{\Delta \,{{i}_{B}}} \right)}_{{{V}_{CE}}}}\]


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