A) \[CHC{{l}_{3}}/NaOH\]
B) \[CC{{l}_{4}}/NaOH\]
C) \[C{{H}_{2}}C{{l}_{2}}/NaOH\]
D) \[C{{H}_{3}}Cl/NaOH\]
Correct Answer: A
Solution :
Key Idea: This reaction is Reimer-Tiemann reaction with \[CHC{{l}_{3}}\] and aq. alkali \[(NaOH)\] phenol gives salicylaldehyde and with \[CC{{l}_{4}}\]and \[NaOH\] phenol gives salicylic acid.
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