DUMET Medical DUMET Medical Solved Paper-2004

  • question_answer
    The boiling point of benzene is 353.23 K. When 1.80 g of a nonvolatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. The molar mass of the solute is : [\[{{K}_{b}}\] for benzene = 2.53 K kg \[mo{{l}^{-1}}\]]

    A)  5.8 g \[mo{{l}^{-1}}\]

    B)  0.58 g \[mo{{l}^{-1}}\]

    C)  58 g \[mo{{l}^{-1}}\]

    D)  0.88 g \[mo{{l}^{-1}}\]

    Correct Answer: C

    Solution :

    Key Idea: Use the following formula to find the molecular mass of solute. \[M=\frac{{{K}_{b}}\times 1000\times w}{\Delta {{T}_{b}}\times W}\] where, w = weight of solute = 1.80 g W = weight of solvent = 90 g \[\Delta {{T}_{b}}=\] elevation in boiling point \[=354.11\,K-353.23\,K=0.88\,K\] \[{{K}_{b}}=2.53\,K\,kg\,mo{{l}^{-1}}\] \[\therefore \] \[M=\frac{2.53\times 1000\times 1.80}{0.88\times 90}\] \[=58\,g\,mo{{l}^{-1}}\]


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