A) 5.5 mm, 60 kHz
B) 330 m, 60 kHz
C) 5.5 mm, 30 kHz
D) 5.5 mm, 80 kHz
Correct Answer: A
Solution :
When wave travels from one medium to another, its velocity changes while frequency remains same. Also, there is change in intensity of wave. Hence, frequency is 60 kHz. Also, \[n=\frac{v}{\lambda }\] where n is frequency, v is speed of sound in air, and \[\lambda \] is wavelength. \[\therefore \lambda =\frac{v}{n}=\frac{330}{60\times {{10}^{3}}}=5.5\times {{10}^{-3}}m=5.5\,mm\]
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