2. Solved Papers
  3. DUMET Medical

DUMET Medical DUMET Medical Solved Paper-2004

  • question_answer
    An engine pumps up 100 kg of water trough a height of 10 m in 5 s. Given that the efficiency of the engine is 60%. If \[g=10\,m{{s}^{-2}}\], the power of the engine is :

    A)  3.3 kW       

    B)  0.33 kW

    C)  0.033 kW     

    D)  33 kW

    Correct Answer: A

    Solution :

     Key Idea: Water possesses potential energy due to its height The rate of doing work by a machine is called its power. Power\[=\frac{work}{time}\] In terms of efficiency \[(\eta )\] Power \[=\frac{work/time}{\eta }\] Given, \[\eta =\frac{60}{100},\,\,W=mgh=100\times 10\times 10\], \[t=5\,s\] s. \[\therefore \] \[P=\frac{100\times 10\times 10}{5}\times \frac{100}{60}\] \[\Rightarrow \] \[P=3.3\times {{10}^{3}}W\] \[P=3.3\,\,kW\]


You need to login to perform this action.
You will be redirected in 3 sec spinner