A) 5.5V
B) 1.5V
C) 9.5V
D) 4.0V
Correct Answer: D
Solution :
Key Idea: Stopping potential is a measure of the maximum kinetic energy of the electrons. The negative potential at which photoelectric current becomes zero is called stopping potential \[({{V}_{s}})\] or cut-off potential. That is, \[{{E}_{k}}=e{{V}_{0}}\] where \[{{E}_{k}}\] is maximum kinetic energy of photo electrons. Given \[{{E}_{k}}=4\,eV=4\times 1.6\times {{10}^{-19}}V\] and \[e=1.6\times {{10}^{-19}}C\] \[\Rightarrow \] \[{{V}_{0}}=\frac{{{E}_{k}}}{e}=\frac{4\times 1.6\times {{10}^{-19}}}{1.6\times {{10}^{-19}}}=4\,V\]
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