A) 1/4
B) 1/2
C) 1/8
D) 1/16
Correct Answer: D
Solution :
The sample left after n half-lives is \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] where \[{{N}_{0}}\] is original amount of sample. \[\therefore \] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] where \[n=\frac{6400}{1600}=4\] \[\therefore \] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{4}}=\frac{1}{16}\]
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