A) zero
B) +4
C) +2
D) + 6
Correct Answer: B
Solution :
Key Idea: The sum of oxidation state of all elements in compound is zero. Let oxidation state of \[N=x\] \[HN{{O}_{3}}\] \[{{N}_{2}}O\] \[+1+x+(-2\times 3)=0\] \[2x+(-2)=0\] \[\therefore x=+5\] \[\therefore x=+1\] \[\therefore \] Change in oxidation state = (+5) - (+1) = + 4You need to login to perform this action.
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