A) \[3.01\times {{10}^{12}}\]
B) \[30.1\times {{10}^{23}}\]
C) \[3.01\times {{10}^{24}}\]
D) \[3.01\times {{10}^{20}}\]
Correct Answer: A
Solution :
Key Idea: Use Avogadros law to solve the problem. \[22.4\,L=22400\,cc\] \[\because \] 22400 cc contains \[=6.023\times {{10}^{23}}\] molecules \[\therefore \] \[1.12\times {{10}^{-7}}cc\] contains \[=\frac{6.023\times {{10}^{23}}}{22400}\times 1.12\times {{10}^{-7}}\] \[=3.01\times {{10}^{12}}\] molecules
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