A) \[SOC{{l}_{2}}\]
B) \[C{{l}_{2}}\]
C) \[NaCl\]
D) \[KCl\]
Correct Answer: A
Solution :
\[\underset{\begin{smallmatrix} ethyl \\ alcohol \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\,\,+\,\,\underset{\begin{smallmatrix} thionyl \\ chloride \end{smallmatrix}}{\mathop{SOC{{l}_{2}}}}\,\to \underset{\begin{smallmatrix} ethyl \\ chloride \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{5}}Cl}}\,+S{{O}_{2}}+HCl\] Ethyl alcohol is converted into ethyl chloride either by reacting with \[SOC{{l}_{2}}\] or P and \[C{{l}_{2}}\] or \[PC{{l}_{3}}\] or \[ZnC{{l}_{2}}\] and \[HCl\].
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