A) \[FeC{{l}_{3}}\]
B) \[AlC{{l}_{3}}\]
C) \[B{{F}_{3}}\]
D) \[N{{H}_{3}}\]
Correct Answer: D
Solution :
Key Idea: Electron deficient compounds or electron acceptors are Lewis acids. (i) \[B{{F}_{3}}\] and \[AlC{{l}_{3}}\] are Lewis acids because B in \[B{{F}_{3}}\] and Al in \[AlC{{l}_{3}}\] are electron deficient atoms (They have 6 electrons each in their valence shell) (ii) \[FeC{{l}_{3}}\] is Lewis acid because it can accept electrons in vacant d orbital. (iii) \[N{{H}_{3}}\] is not Lewis acid because it has lone pair of electron (at N). Infact it is Lewis base (there fore it is electron donor.) \[\therefore \] Correct answer is choice [d] \[N{{H}_{3}}\]
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