A) 100
B) 10.1
C) 10
D) 1.01
Correct Answer: A
Solution :
Key Idea: Molecular weight of solute is calculated by using following formula. \[{{M}_{B}}=\frac{{{K}_{b}}\times {{W}_{B}}\times 1000}{\Delta {{T}_{b}}\times {{W}_{a}}}\] where, \[{{M}_{B}}=\] molecular v/eight of solute \[{{W}_{B}}=\] weight of solute = 0.15 g \[\Delta {{T}_{b}}=\] elevation in boiling point \[={{0.216}^{o}}C\] \[{{W}_{a}}=\] weight of solvent = 15.0 g \[{{K}_{b}}=2.16\] \[\therefore \] \[{{M}_{B}}=\frac{2.16\times 0.15\times 1000}{0.216\times 15}\] = 100
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