A) \[1.05\times {{10}^{5}}J\]
B) \[1.0\times {{10}^{4}}J\]
C) \[15\times {{10}^{4}}J\]
D) none of these
Correct Answer: A
Solution :
The engine does work to overcome the frictional forces and providing kinetic energy to the car. \[\therefore \] \[W=Fd+\frac{1}{2}m{{v}^{2}}\] Given, \[W=Fd+\frac{1}{2}m{{v}^{2}}\], \[m=500\,kg,\,v=20\,m/s\] \[\therefore \] \[W=500\times 10+\frac{1}{2}\times 500\times {{(20)}^{2}}\] \[W=1.05\times {{10}^{5}}J\].
You need to login to perform this action.
You will be redirected in
3 sec
