A) two alkanes
B) four alkanes
C) three alkanes
D) one alkane
Correct Answer: C
Solution :
Key Idea: When different alkyl halides react with sodium in presence of ether, a mixture of alkanes is formed. \[C{{H}_{3}}C{{H}_{2}}Cl+Na+C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Cl\xrightarrow{Ether}\] \[\underset{butane}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,+\underset{pentane}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\] \[+\underset{hexane}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\] \[\therefore \] Three alkanes are formed.
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