A) 10 A, 0.005s
B) 15 A, 0.05s
C) 12 A, 0.05s
D) 8 A, 0.01s
Correct Answer: A
Solution :
The root-mean-square (rms) value of an alternating current is defined as the square-root of the average of \[{{i}^{2}}\] during a complete cycle, where i is the instantaneous value of alternating current. \[\therefore \] \[{{i}_{rms}}=\frac{{{i}_{0}}}{\sqrt{2}}\] \[({{i}_{0}}=\]peak value of current) Given, \[{{i}_{0}}=14.14\,A\] \[\therefore \] \[{{i}_{rms}}=\frac{14.14}{\sqrt{2}}=\frac{14.14}{1.414}=10\,A\] Also, time period \[=\frac{1}{frequency}=\frac{1}{50}s\] Time taken to rise from zero to maximum value is \[T=\frac{T}{4}=\frac{1}{50\times 4}=\frac{1}{200}s=0.005\,s\].You need to login to perform this action.
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