A) \[1575\,\overset{o}{\mathop{A}}\,\]
B) \[1868\,\overset{o}{\mathop{A}}\,\]
C) \[2875\,\overset{o}{\mathop{A}}\,\]
D) \[3921\,\overset{o}{\mathop{A}}\,\]
Correct Answer: B
Solution :
The minimum energy required for the emission of photoelectron from a metal is called the work function of that metal. The wavelength corresponding to work function is threshold wavelength. \[W=h{{v}_{0}}=\frac{hc}{{{\lambda }_{0}}}\] where h is Plancks constant and c is speed of light. Given, \[W=6.626\,eV=6.626\times 1.6\times {{10}^{-19}}J\] \[h=6.6\times J-s,\,c=3\times {{10}^{8}}m/s\] \[\therefore \] \[\lambda =\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{6.626\times 1.6\times {{10}^{-19}}}\] \[\lambda =1868\times {{10}^{-10}}m=1868\,\overset{o}{\mathop{A}}\,\]
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