A) 0.2eV
B) 0.47eV
C) 1.5eV
D) 2eV
Correct Answer: B
Solution :
When Wheatstone bridge is balanced, ratio of resistances connected in opposite arms of the bridge is same. \[\therefore \] \[\frac{P}{Q}=\frac{R}{S}\] \[\Rightarrow \] \[\frac{10}{100}=\frac{70}{S}\] \[\Rightarrow \] \[S=\frac{70\times 100}{10}=700\,\Omega \]You need to login to perform this action.
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