DUMET Medical DUMET Medical Solved Paper-2002

  • question_answer
    At what temperature the speed of sound in air will become double of its value at \[{{27}^{o}}C\]?

    A)  \[{{54}^{o}}C\]         

    B)  \[{{627}^{o}}C\]

    C)  \[{{927}^{o}}C\]        

    D)  \[{{327}^{o}}C\]

    Correct Answer: C

    Solution :

    According to Laplace, the formula for speed of sound in a gas is \[v=\sqrt{\frac{\gamma \,RT}{M}}\] where \[\gamma \] is ratio of specific heats, R is gas constant, T is temperature and M is molecular weight. Given, \[{{v}_{1}}=v,\,{{v}_{2}}=2\,v,\,{{T}_{1}}={{27}^{o}}C\] \[=273+27=300\,K\] \[\therefore \] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] \[\Rightarrow \] \[\frac{v}{2\,v}=\sqrt{\frac{300}{{{T}_{2}}}}\] \[\Rightarrow \] \[{{T}_{2}}=300\times 4=1200\,K\] \[=1200-273={{927}^{o}}C\]. Note: In general the velocity of sound in air increases roughly by \[0.61\,m{{s}^{-1}}\] per degree centigrade rise in temperature.


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