A) \[{{490}^{o}}C\]
B) \[{{49}^{o}}C\]
C) \[{{0.49}^{o}}C\]
D) \[{{4.9}^{o}}C\]
Correct Answer: C
Solution :
Key Idea: Potential energy due to waterfall is converted into heat. Water possesses potential energy due to its height \[h=mgh\] Thermal energy \[=mc\,\Delta \,\theta \] where c is specific heat of water, \[\Delta \,\theta \] is change in temperature and m is mass of water fall. From law of conservation of energy \[mgh=(mc\,\Delta \theta )\times 4.2\times {{10}^{3}}\] Given, \[g=9.8\,m/{{s}^{2}},h=210\,m,c=1\,J/k{{g}^{o}}C\] \[\therefore \] \[\Delta \theta =\frac{9.8\times 210}{4.2\times {{10}^{3}}\times 1}={{0.49}^{o}}C\]
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