A) 7 %
B) 10 %
C) 20 %
D) 5 %
E) 9 %
Correct Answer: A
Solution :
Given, \[V=\left( 50\pm 4 \right)V\] \[I=\left( 20\pm 0.4 \right)\,A\] Now, from Ohms law, \[V=IR\] \[\therefore \] \[R=\frac{V}{I}\] Maximum percentage error in resistance i.e., \[\frac{\Delta R}{R}\times 100=\left( \frac{\Delta V}{V}\times 100 \right)+\left( \frac{\Delta I}{I}\times 100 \right)\] \[=\frac{4}{50}\times 100+\frac{0.4}{20}\times 100\] \[=8+2=10%\]You need to login to perform this action.
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