CMC Medical CMC-Medical VELLORE Solved Paper-2014

  • question_answer
    If the sum of a number of two digits and a numbers formed by reversing the digits is 99, then what is the sum of the digits of the original number?

    A)  9

    B)  81

    C)  Cannot be known

    D)  18

    Correct Answer: A

    Solution :

                    Let the number of two digits is \[\left( 10x+y \right)\] \[\therefore \]The number formed by reversing the digits \[=10y+x\] \[\therefore \] \[10x+y+10y+x=99\] \[\Rightarrow \]               \[11x+11y=99\] \[\therefore \]  \[(x+y)=\frac{99}{11}=9\]


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