A) \[2\times {{10}^{-5}}T\]
B) \[4\times {{10}^{-5}}T\]
C) \[8\times {{10}^{-5}}T\]
D) \[1.2\times {{10}^{-5}}T\]
Correct Answer: B
Solution :
\[{{B}_{1}}=\frac{{{\mu }_{0}}I}{4\pi a}(\sin {{\phi }_{1}}+\sin {{\phi }_{2}})\] \[\tan 30{}^\circ =\frac{a}{\left( \frac{I}{2} \right)}\] \[a=\frac{I}{2\sqrt{3}}\] \[B=\frac{{{\mu }_{0}}I}{4\pi \left( \frac{I}{2\sqrt{3}} \right)}(\sin 60+\sin 60)\] \[{{B}_{1}}=\frac{6{{\mu }_{0}}I}{4\pi I}\] \[{{B}_{total}}=3\,{{B}_{1}}\] \[{{B}_{total}}=4\times {{10}^{-5}}T\]You need to login to perform this action.
You will be redirected in
3 sec