A) It may decay by position emission
B) It may decay by a neutron emission
C) It may decay by electron capture
D) The product nucleus is Mg
Correct Answer: B
Solution :
\[A{{l}^{25}}\]has \[13p\]and \[12\,n,\]i.e., \[\frac{n}{p}<1\] Such nuclei lie below the band of stability, decay by either positron emission or electron capture of\[M{{g}^{25}}\]as \[{}_{13}^{25}Al\xrightarrow{{}}{}_{+1}^{0}e+{}_{12}^{25}Mg\]
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