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CMC Medical CMC-Medical VELLORE Solved Paper-2012

  • question_answer
    The periodic time of a particle executing SHM is 4 s. The time taken by it to go from its mean position to half the maximum displacement (amplitude) is

    A)  \[1s\]                                  

    B)  \[2s\]

    C)  \[\frac{1}{3}s\]                                

    D)  \[\frac{2}{3}s\]

    Correct Answer: C

    Solution :

                    \[y=A\,\,\sin \left( \frac{2\pi }{T} \right)t\] \[\Rightarrow \]               \[\frac{A}{2}=A\,\,\sin \left( \frac{2\pi }{4} \right)t\] \[\Rightarrow \]               \[\frac{\pi t}{2}=\frac{\pi }{6}\Rightarrow \,t=\frac{1}{3}s\]


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