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CMC Medical CMC-Medical VELLORE Solved Paper-2012

  • question_answer
    If a resonant AC circuit contains a capacitor of capacitance \[{{10}^{-6}}F\] and an inductor of \[{{10}^{-4}}H,\] then the frequency of electrical oscillations will be

    A)  \[10\,Hz\]                          

    B)  \[{{10}^{5}}\,Hz\]

    C)  \[\frac{10}{2\pi }\,Hz\]                

    D)  \[\frac{{{10}^{5}}}{2\pi }\,Hz\]

    Correct Answer: D

    Solution :

                    The frequency of electrical osculation. \[v=\frac{1}{2\pi \sqrt{LC}}=\frac{1}{2\pi \sqrt{{{10}^{-6}}\times {{10}^{-4}}}}\]\[=\frac{{{10}^{5}}}{2\pi }Hz\]


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