A) \[2.5\times {{10}^{-3}}kg\text{-}{{m}^{2}}\]
B) \[4\times {{10}^{-2}}kg\text{-}{{m}^{2}}\]
C) \[5\times {{10}^{-3}}kg\text{-}{{m}^{2}}\]
D) \[5.5\times {{10}^{-3}}kg\text{-}{{m}^{2}}\]
Correct Answer: A
Solution :
The moment of inertia \[I=\frac{1}{4}m{{r}^{2}}\] \[\therefore \] \[I=\frac{1\times {{(0.1)}^{2}}}{4}=\frac{1\times 1\times {{10}^{-2}}}{4}\] \[=2.5\times {{10}^{-3}}kg\text{-}{{m}^{2}}\]
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