A) \[\sqrt{2}:1\]
B) \[1:1\]
C) \[4:1\]
D) \[2:1\]
Correct Answer: D
Solution :
Resultant intensity, \[I=4{{I}_{0}}{{\cos }^{2}}(\phi /2)\] \[\therefore \] Ratio of intensity for two waves \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{{{\cos }^{2}}({{\phi }_{1}}/2)}{{{\cos }^{2}}({{\phi }_{2}}/2)}\] \[=\frac{{{\cos }^{2}}0{}^\circ }{{{\cos }^{2}}(90{}^\circ /2)}=\frac{2}{1}\]You need to login to perform this action.
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