A) \[C{{a}^{2+}}>{{K}^{+}}>C{{l}^{-}}>{{S}^{2-}}\]
B) \[C{{l}^{-}}>{{S}^{2-}}>{{K}^{+}}>C{{a}^{2+}}\]
C) \[C{{a}^{2+}}>C{{l}^{-}}>{{K}^{+}}>{{S}^{2-}}\]
D) \[{{K}^{+}}>{{S}^{2-}}>C{{l}^{-}}>C{{a}^{2+}}\]
E) \[{{S}^{2-}}>C{{l}^{-}}>{{K}^{+}}>C{{a}^{2+}}\]
Correct Answer: E
Solution :
Ionic radii\[\propto \frac{1}{{{Z}_{eff}}}\]\[\propto \text{negative}\,\text{charge}\,\propto \frac{\text{1}}{\text{positive}\,\text{charge}}\] Thus, the correct order of ionic radii of these ions is \[{{S}^{2-}}>C{{l}^{-}}>{{K}^{+}}>C{{a}^{2+}}\]
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