A) \[C{{N}^{-}}\]
B) \[CO\]
C) \[{{F}^{-}}\]
D) \[N{{H}_{3}}\]
E) None of these
Correct Answer: C
Solution :
The value of \[{{\Delta }_{o}}\] depends upon the splitting of d-orbitals by the ligand. On the basis of splitting power ligands are arranged in a series, called petrochemical series. \[{{I}^{-}}<B{{r}^{-}}<C{{l}^{-}}<{{F}^{-}}<O{{X}^{-}}\approx {{H}_{2}}O<py\] \[\approx N{{H}_{3}}<en<NO_{2}^{-}<C{{N}^{-}}<CO\] Hence \[{{F}^{-}}\]has the lowest \[{{\Delta }_{o}}\]value.
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