A) \[\frac{1}{\sqrt{2}}\]
B) \[\sqrt{2}\]
C) \[2\sqrt{2}\]
D) \[\frac{1}{2\sqrt{2}}\]
E) None of these
Correct Answer: B
Solution :
Given, \[A=60{}^\circ ,\]\[{{\delta }_{m}}=30{}^\circ \] As, \[\mu =\sin \frac{\left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \left( \frac{A}{2} \right)}\] \[\therefore \] \[\mu =\sin \frac{\left( \frac{60{}^\circ +30{}^\circ }{2} \right)}{\sin \left( \frac{60{}^\circ }{2} \right)}\] \[=\frac{\sin 45{}^\circ }{\sin 30{}^\circ }\] \[=\frac{1\text{/}\sqrt{2}}{1\text{/}2}\] \[=\frac{2}{\sqrt{2}}\] \[=\sqrt{2}\]
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