A) \[\frac{2\times {{10}^{-19}}}{{{\mu }_{0}}}\]
B) \[2\times {{10}^{-19}}{{\mu }_{0}}\]
C) \[{{10}^{-19}}{{\mu }_{0}}\]
D) \[\frac{{{10}^{-19}}}{{{\mu }_{0}}}\]
E) None of these
Correct Answer: C
Solution :
The magnetic field at the centre of a circle is given by \[B=\frac{{{\mu }_{0}}i}{2r}\] where, \[i\] is current and r the radius of circle. Also, \[i=\frac{q}{t}\] For helium nucleus, \[q=2e\] \[\therefore \] \[i=\frac{2e}{t}\] So, \[B=\frac{{{\mu }_{0}}.\,2e}{2rt}\] \[=\frac{{{\mu }_{0}}\times 2\times 1.6\times {{10}^{-19}}}{2\times 0.8\times 2}\] \[={{10}^{-19}}{{\mu }_{0}}\]
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