CMC Medical CMC-Medical VELLORE Solved Paper-2010

  • question_answer
    A weight of 290 N and another of 200 N are suspended by a rope on either side of a frictionless pulley. The acceleration of each weight is

    A)  1.5 \[m\text{/}{{s}^{2}}\]           

    B)  1.8 \[m\text{/}{{s}^{2}}\]

    C)  2.2 \[m\text{/}{{s}^{2}}\]           

    D)  2.5 \[m\text{/}{{s}^{2}}\]

    E)  None of these

    Correct Answer: B

    Solution :

                    Acceleration, \[a=\left( \frac{{{m}_{2}}-{{m}_{1}}}{{{m}_{2}}+{{m}_{1}}} \right)g\] \[\Rightarrow \]               \[a=\left( \frac{{{W}_{2}}-{{W}_{1}}}{{{W}_{2}}+{{W}_{1}}} \right)g\] \[=\left( \frac{290-200}{290+200} \right)\times 9.8\] \[\Rightarrow \]               \[a=\frac{90\times 9.8}{490}\] \[\Rightarrow \]               \[a=1.8\,m\text{/}{{s}^{2}}\]


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