A) 18 v
B) 12 v
C) 6 v
D) 3 v
E) None of these
Correct Answer: C
Solution :
Maximum velocity \[{{v}_{\max }}=A\omega \] \[\omega =\frac{2\pi }{T}\] \[\therefore \] \[{{v}_{\max }}=\frac{2\pi A}{T}\] \[v\propto \frac{A}{T}\] \[\therefore \] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{{{A}_{1}}}{{{A}_{2}}}\times \frac{{{T}_{2}}}{{{T}_{1}}}\] \[=\frac{1}{2}\times \frac{1}{3}=\frac{1}{6}\] \[{{v}_{2}}=6{{v}_{1}}\] \[=6\,v\]
You need to login to perform this action.
You will be redirected in
3 sec
