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CMC Medical CMC-Medical VELLORE Solved Paper-2010

  • question_answer
    What is the empirical formula of vanadium oxide if 2.74 g of metal oxide contains 1.53 g of metal?

    A)  \[{{V}_{2}}{{O}_{3}}\]                  

    B)  \[VO\]

    C)  \[{{V}_{2}}{{O}_{5}}\]                  

    D)  \[{{V}_{2}}{{O}_{7}}\]

    E)  None of these

    Correct Answer: C

    Solution :

                    Percentage of \[V=\frac{1.53}{2.74}\times 100=55.83\] \[\therefore \] of \[O=44.17\]
    Element Percentage Atomic ratio Simplest ratio
    V 55.83 \[\frac{55.83}{52}=1.1\] \[\frac{1.1}{1.1}=1\]
    O 44.17 \[\frac{44.17}{16}=2.76\] \[\frac{2.76}{1.1}=2.5\]
    \[V:O=2:5\] Thus, empirical formula\[={{V}_{2}}{{O}_{5}}\]


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