A) \[\sqrt{2}\]F
B) 2 F
C) \[\sqrt{2}\]F
D) 3 F
Correct Answer: C
Solution :
Net force on each charge will be \[{{F}_{net}}=\sqrt{{{F}^{2}}+{{F}^{2}}+2{{F}^{2}}\cos 60{}^\circ }\] \[\Rightarrow \] \[{{F}_{net}}=\sqrt{2{{F}^{2}}+2{{F}^{2}}\times \frac{1}{2}}\] \[\Rightarrow \] \[{{F}_{net}}=\sqrt{2{{F}^{2}}+{{F}^{2}}}\] \[\Rightarrow \] \[{{F}_{net}}=\sqrt{3{{F}^{2}}}\] \[\therefore \] \[{{F}_{net}}=\sqrt{3}F\]
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