A) \[\frac{V}{n}\]
B) \[nV\]
C) \[n{{V}^{2}}\]
D) \[{{n}^{2/3}}V\]
Correct Answer: D
Solution :
Charge on big drop\[Q=nq\] Capacitance of big-drop \[C={{n}^{1/3}}C\] Hence, potential of big drop \[V=\frac{Q}{C}-\frac{nq}{{{n}^{1/3}}C}={{n}^{2/3}}V\]You need to login to perform this action.
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