A) 20 g \[\text{mo}{{\text{l}}^{-1}}\]
B) 36 g \[\text{mo}{{\text{l}}^{-1}}\]
C) 63 g \[\text{mo}{{\text{l}}^{-1}}\]
D) 81 g \[\text{mo}{{\text{l}}^{-1}}\]
Correct Answer: D
Solution :
\[pH=0.908=-\,\log \,[{{H}^{+}}]\] \[[{{H}^{+}}]=0.1235\,M=[Acid]\] \[m\] mol of acid = 12.35 Molar mass\[=\frac{1000}{12.35}=80.97\approx 81\,g\,mo{{l}^{-1}}\]
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