A) \[18\,c{{m}^{3}}\]
B) \[22400\,c{{m}^{3}}\]
C) \[6.02\times {{10}^{-23}}c{{m}^{3}}\]
D) \[3.0\times {{10}^{-23}}\,c{{m}^{3}}\]
Correct Answer: D
Solution :
Mass of one molecule of water \[=\frac{\text{mol}\text{.}\,\text{mass}}{{{\text{N}}_{\text{0}}}}=\frac{18}{6.02\times {{10}^{23}}}g\] \[\therefore \] Volume of 1 molecule of water\[=\frac{\text{mass}}{\text{density}}\] \[=\frac{18\times {{10}^{-23}}}{6.02\times 1}\] \[=3\times {{10}^{-23}}mL\]
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