A) 662
B) 1324
C) 66.2
D) 6.62
Correct Answer: A
Solution :
\[E=3\times {{10}^{-12}}erg\] \[\lambda =?\] \[h=6.62\times {{10}^{-27}}\,erg\text{-}s\] \[c=3\times {{10}^{10}}\,cm\,{{s}^{-1}}\] \[E=\frac{hc}{\lambda }\] \[3\times {{10}^{-2}}=\frac{6.62\times {{10}^{-27}}\times 3\times {{10}^{10}}}{\lambda }\] \[\lambda =\frac{6.62\times {{10}^{-27}}\times 3\times {{10}^{10}}}{3\times {{10}^{-12}}}\] \[=6.62\times {{10}^{-5}}\,cm\] \[=6.62\times {{10}^{-7}}\,cm\] \[=662\times {{10}^{-9}}\,m=662\text{ }nm\]
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