question_answer

In a 120 L of solution of acid and water, acid is 75%. A person takes out 20 L of this solution and added 16.2 L of acid and 3.8 L of water in the remaining solution. What is the percentage of water in the final solution?

A) 22                    

B)        24

C) 25                    

D)        28

Correct Answer: B

Solution :

Sol.

Solution = 120 L

Acid =75% of 120= 90 L

Water = 120 - 90 = 30 L

When a person takes out 20 L of solution amount of acid and water is 15 L and 5 L is taken out.

Remaining acid Remaining water

Now 16.2 L of acid is added and 3.8 L of water is added

\[\therefore \]Acid            Water

\[\therefore \]  Percentage of water

\[=\frac{128}{120}\times 100\]

\[=\frac{288}{12}=24\]%