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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2011

  • question_answer
    For a diatomic gas, change in internal energy for unit change in temperature at constant pressure and constant volume is \[{{U}_{1}}\] and \[{{U}_{2}}\] respectively. \[{{U}_{1}}:{{U}_{2}}\] is

    A)  5 : 3                                      

    B)  3 : 5

    C)  1:1                                        

    D)  7 : 5

    Correct Answer: D

    Solution :

    At constant pressure, change in internal energy for unit change in temperature \[{{U}_{1}}={{C}_{P}}\] At constant volume \[{{U}_{2}}={{C}_{V}}\] \[\therefore \]  \[\frac{{{U}_{1}}}{{{U}_{2}}}=\frac{{{C}_{P}}}{{{C}_{V}}}=\gamma \] For diatomic gas \[\gamma =1.4\]                                 \[\frac{{{U}_{1}}}{{{U}_{2}}}=1.4\] \[\Rightarrow \]                               \[\frac{{{U}_{1}}}{{{U}_{2}}}=\frac{7}{5}\]


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