A) 2 : 1
B) 1 : 2
C) 1 : 4
D) 1 : 1
Correct Answer: B
Solution :
Moment of inertia of ring \[I=m{{r}^{2}}\] \[\frac{{{I}_{1}}}{{{I}_{2}}}=\left( \frac{{{m}_{1}}}{{{m}_{2}}} \right){{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}\] Given, \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{2}{1}\] And \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{2}{1}\] \[\frac{2}{1}=\left( \frac{{{m}_{1}}}{{{m}_{2}}} \right){{\left( \frac{2}{1} \right)}^{2}}\] Hence, \[\frac{{{m}_{1}}}{{{m}_{2}}}=1:2\]
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