Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2010

  • question_answer
    A car of mass m is taking a circular turn of radius r on a frictional level road with a speed v. In order that the car does not skid (\[\mu =\] coefficient  of friction)

    A) \[\frac{m{{v}^{2}}}{r}\ge \mu mg\]                        

    B) \[\frac{m{{v}^{2}}}{r}\le \mu mg\]

    C) \[\frac{m{{v}^{2}}}{r}=\mu mg\]                              

    D) \[\frac{v}{r}=\mu g\]

    Correct Answer: B

    Solution :

    When a vehicle takes a turn on a circular path it requires centripetal force. If friction provides this centripetal force then vehicle can move in circular path safely. ie. Friction force >. Required centripetal force\[\mu mg\ge \frac{m{{v}^{2}}}{r}\]


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