Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2010

  • question_answer
    A body of mass 2 kg slides down a curved track which is quadrant of a circle of radius 1m (figure) All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is

    A)  4.43 m/s                             

    B)  2 m/s

    C)  0.5 m/s                               

    D)  19.6 m/s

    Correct Answer: A

    Solution :

    By applying law of conservation of energy \[mgR=\frac{1}{2}m{{v}^{2}}\]                 \[\Rightarrow \]               \[v=\sqrt{2Rg}\]                                 \[=\sqrt{2\times 1\times 10}\]                                 \[=4.43m/s\]


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