A) \[{{S}_{N}}1\] mechanism
B) \[{{S}_{N}}2\] mechanism
C) Any of [a] and [b]
D) None of the above
Correct Answer: A
Solution :
Tertiary halide preferentially undergo \[{{S}_{N}}1\]substitution as they can give stable carbocation. \[\underset{t-butyl\,chloride}{\mathop{{{H}_{3}}C-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-Cl}}\,\xrightarrow[-Cl]{slow}\underset{(most\,stable)}{\mathop{\underset{{{3}^{o}}\,\,carbocation}{\mathop{{{({{H}_{3}}C)}_{3}}{{C}^{+}}}}\,}}\,\xrightarrow[fast]{+O{{H}^{-}}}\underset{t-butyl\,alcohol}{\mathop{{{({{H}_{3}}C)}_{3}}COH}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
