A) fluorine from \[NaF\]
B) iodine from \[NaI\]
C) bromine from \[NaBr\]
D) None of these
Correct Answer: A
Solution :
The sequence of oxidising nature of halogens are follows: \[Fluorine>Chlorine>Bromine>Iodine\] So, chlorine displace bromine from \[NaBr\]and iodine from \[NaI\]but it can't displace fluorine from \[NaF\]. \[NaF+C{{l}_{2}}\xrightarrow{{}}No\,reaction\] \[2NaBr+C{{l}_{2}}\xrightarrow{{}}2NaCl+B{{r}_{2}}\] \[2NaI+C{{l}_{2}}\xrightarrow{{}}2NaCl+{{I}_{2}}\]
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