A) diminished, upright, virtual
B) enlarged, upright, virtual
C) diminished, inverted, real
D) enlarged, upright, real
Correct Answer: B
Solution :
\[u=-10cm\] \[f=-20cm\] Using mirror formula, \[\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\] \[-\frac{1}{20}=\frac{1}{v}+\frac{1}{(-10)}\] \[\therefore \] \[\frac{1}{v}=-\frac{1}{20}+\frac{1}{10}=\frac{1}{20}\] \[v=20cm\] Magnification \[(m)=-\frac{v}{u}=-\frac{20}{(-10)}\] \[=2\] Therefore, magnified (enlarged), upright and virtual image is formed.
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