Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    The amount of work done in forming a soap film of size \[10cm\times 10cm\] (Surface tension  \[T=3\times {{10}^{-2}}N/m\]) is

    A)  \[6\times {{10}^{-4}}\text{J}\]                                 

    B)  \[3\times {{10}^{-4}}\text{J}\]

    C)  \[6\times {{10}^{-3}}\text{J}\]                                 

    D)  \[6\times {{10}^{-2}}\text{J}\]

    Correct Answer: A

    Solution :

    Work done \[W=T\,\Delta A\] Since soap film has two surfaces, therefore \[\Delta A=2\times (10\times 10)c{{m}^{2}}=2\times {{10}^{-2}}{{m}^{2}}\] \[\therefore \]  \[W=T\,\Delta \,A=3\times {{10}^{-2}}\times 2\times {{10}^{-2}}=6\times {{10}^{-4}}J\]


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