A) radium
B) carbon
C) lead
D) neptunium
Correct Answer: C
Solution :
Uranium ultimately decay into a stable isotopes lead in this series. \[_{92}{{U}^{238}}{{\xrightarrow{-\alpha }}_{90}}T{{h}^{234}}{{\xrightarrow{-\beta }}_{91}}P{{a}^{234}}{{\xrightarrow{-\beta }}_{92}}{{U}^{234}}\]\[{{\xrightarrow{-\alpha }}_{90}}T{{h}^{230}}{{\xrightarrow{-\alpha }}_{88}}R{{a}^{226}}{{\xrightarrow{-\alpha }}_{86}}R{{n}^{222}}\] \[{{\xrightarrow{-\alpha }}_{84}}P{{o}^{218}}{{\xrightarrow{-\alpha }}_{82}}P{{b}^{214}}{{\xrightarrow{-\beta }}_{83}}B{{i}^{214}}\] \[{{\xrightarrow{-\beta }}_{84}}P{{o}^{214}}{{\xrightarrow{-\alpha }}_{82}}P{{b}^{210}}{{\xrightarrow{-\beta }}_{83}}B{{i}^{210}}\] \[{{\xrightarrow{-\beta }}_{84}}P{{o}^{210}}{{\xrightarrow{-\alpha }}_{82}}P{{b}^{206}}\]
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